$\int\frac{4u^9}{\left(u^5+3\right)^3}du$
$125x^3-512$
$3-\left(4-10\right)+7$
$\left(4x\cdot5y\right)^2$
$2\cdot3^2$
$\int\frac{1}{x^2\left(x+4x+9\right)}dx$
$x^4-8^2-128$
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