$4x=3x+5$
$\lim_{x\to\infty}\left(\frac{-5}{4x+3}\right)$
$\frac{1+cosx}{1-\:cosx}=1+\frac{2cosx\left(1+cosx\right)}{sin^2x}$
$.95\:+\:2.1$
$\frac{d}{dx}z$
$c+3c+5c$
$-4x+3y+x-2z+2y$
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