$\int\frac{1}{4x+6}dx$
$-4\cdot\left(-14\right)\cdot\left(-24\right)$
$y^5\:.\:y^7$
$5\lim_{x\to1}\left(1\right)-2\lim_{x\to1}\left(-2\right)$
$\left(\sqrt{\:2}-\frac{x}{3}\right)^2$
$\frac{4x}{x^2-4x+4}-\frac{1}{x-2}=\frac{3}{x-2}$
$\left(4x^3y+5y\right)^3$
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