$\frac{4x^2-4x-8}{4x^2-6x-4}$

$\frac{x^4-x^2-6}{x^2+2}$

$\int\left(2x^2\sqrt[3]{\left(x^3+8\right)}\right)dx$

$\int\left(\tan\left(\frac{x}{8}\right)^6\right)dx$

$\int e^{x^2-5x}\left(2x-5\right)\cdot\:\:dx$

$\left(-11\right)\left(0\right)$

$b\left(x+12\right)^2-by^2$