$\frac{dy}{dx}=\frac{10x+qx}{3+x^2}$

$\sin^2\left(\pi x\right)=\sqrt{3}sin\left(\pi x\right)cos\left(\pi x\right)\left|3\le x\le0\right|$

$\left(x-11\right)\left(x+11\right)\cdot$

$\frac{4}{5}-x^2.8x^3-5x+3$

$5x^2-x+4$

$\frac{dy}{dt}=\frac{e^{-3t}}{y^2}$

$3x^2=30x-27$