$1-18h-81h^2$
$-62\:68+8a$
$\left(x-3\right)^2-4=0$
$12x<2x+20$
$\left(\sin\left(1.1779\right)\right)^3\cdot\left(\cos\left(1.1779\right)\right)^4$
$18-\sqrt{-25}$
$5x-12,\:con\:x=2,5$
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