$\frac{5csc\left(u\right)-1}{5csc\left(u\right)+1}=\frac{5-sin\left(u\right)}{5+sin\left(u\right)}$
$\left(\frac{4}{2}\right)^2$
$\left(30\cdot40\right)+296$
$\frac{dy}{dx}=\frac{xy+3x-y-3}{4}$
$121a^2-16$
$y^2+2y-45=0$
$\frac{1}{\sin^2m}-\frac{1}{\tan^2m}=1$
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