$\lim_{h\to0}\left[\frac{\left(sin\left(2x+2h\right)-sin\:2x\right)}{h}\right]$
$x^2-3x=7$
$\lim_{x\to\:\infty\:\:}\left(\sqrt{x^4+2x^3}-\left(x^2+x\right)\right)$
$108x+120$
$8-5+4-3+7$
$-3x^3-18x^6$
$\sqrt{261}$
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