$\left(6y^8\right)^0$
$\frac{1}{\left(x-2\right)}+\frac{1}{\left(x+2\right)}=\frac{4}{\left(x^2-4\right)}$
$\lim_{x\to0}\left(\frac{2x^2}{3x^2+3}\right)$
$x^2+14x-18$
$11-\left(5+2\right)$
$\int\frac{2x-1}{\sqrt{3-2x-x^2}}dx$
$2y''\:+\:6y'-176y\:=\:0$
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