$\frac{d}{dx}\:\arcsec\left(3bx^5\right)$
$1225a^4-256b^2$
$\frac{dy}{dx}\left(x^2-xy-y^2=1\right)$
$\left(6a\:-\:5\right)\:\left(\:6a\:+\:5\right)\:$
$-3\left(2u+3\right)+4u$
$x+y+2^2$
$\int3x^2e^{-x^3+5}\:dx$
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