$\log\left(100\right)+10+100$
$\frac{1}{2}\left(x+5\right)=7.5$
$16\cos\left(-x\right)\cos\left(6x\right)$
$-9+x=3$
$\frac{4x^2-40x^2-5x+25}{x+3}$
$4^3\cdot2^{-3}\cdot8$
$\frac{1+sin\theta\:\:+cos\theta\:}{1-sin\theta\:+cos\theta\:}=\frac{1+sin\theta\:}{cos\theta\:}$
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