$\frac{\left(5sin^2\left(x\right)\right)}{2}$
$2x^2-4x+96=0$
$-x<3x-4$
$\left(2m^5-7\right)\left(2m^5+7\right)$
$40u+\left(\frac{2}{5}\right)u$
$f\left(x\right)=\ln\left(\frac{3x}{4}\right)$
$3-\left\{2+4-\left[5+1-\left(2+3-8\right)\right]-3+9\right\}$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!