$\frac{3x^3-2x^2+3x-8}{3x^2-1}$
$\int\frac{x^2-6x+8}{\left(x-2\right)\left(x+4\right)}dx$
$\sqrt{\left(-2^3\right)}^4\:x\:\left(-1\right)^9$
$3x^2\left(2x-5\right)$
$3-sec^2x$
$6\left(2w+2\right)+3$
$-x^2+10x-9=0$
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