$\frac{\cot\left(x\right)}{1-\sin\left(x\right)}=\tan\left(x\right)+\cot\left(x\right)$
$3\left(\tan\left(45\right)^2\right)+\cot2\left(45\right)-3=0$
$\:7k\:-\:j-10k\:-\:j\:$
$25m^2-81$
$\int\frac{1+6x+10x^2}{x^2+x^3}dx$
$\left(2x\:+\:3b\right)^2$
$36m^{2x}-100n^{4x-6}$
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