$\int x^3\cdot\left(\ln\left(x\right)\:+\:1\right)$
$-\:4\:+\:\left(\:-\:2\:+\:1\:\right)\:+\:5\:-\:\left[\:3\:-\:\left(\:1\:-\:2\:\right)\:+\:4\:\right]\:+\:1\:-\:2\:$
$\int\frac{3x^3-3x}{x^2\left(x^2-15\right)}dx$
$x^2-6x+c=-5+c$
$5x+5$
$\left(\frac{2}{3}x^3-8\right)^2$
$x^2+8x-3=0$
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