$4-1-5$
$13x^2y^2\left(-7^5y^2\right)$
$\frac{dy}{dx}=\frac{3x}{y^3}$
$4\cdota^{2}-26a+16a$
$12\cdot13\cdot4$
$\frac{dy}{dx}\:-\frac{y}{x}=\frac{x}{3y}$
$5x^3y+10x^2y^2+5x^2y$
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