$3x+6\ge2$
$x^2-18x=63$
$\left(3x\right)^2-\left(5\right)^2$
$\frac{3}{8}ab+\frac{1}{4}ab-ab$
$-7x^2+55x+8$
$3x-9<6$
$a^3+\frac{1}{a^3}$
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