$\int\left(\frac{1}{e^{12x}-1}\right)dx$
$4\left(10x+3\right)-12$
$\lim_{x\to1}\left(\frac{x+8}{2x+1}\right)$
$\lim_{x\to6}\left(\left(x+4\right)^3\left(x-5\right)^2\right)$
$\:4y\:-\:2x\:+\:6\:=\:0.$
$\sqrt[27]{97.2}$
$-3\left(-9\right)\cdot\left|-5\right|$
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