$\left(\sqrt[5]{2x^2y}\right)\left(\sqrt[5]{16x^3}y^4\right)$

$3r-r=12$

$f\left(x\right)=\frac{6}{5}x^{-\frac{1}{9}}$

$\frac{2x^3-3x^2-2x}{x-1}$

$\frac{dy}{dx}=x^2\cdot sen\left(2y\right)$

$\int\frac{\left(x^3-x\right)}{\sqrt{x}}dx$

$\lim_{x\to\infty}\left(x^2\left(\sqrt[x]{e}\:-1\right)\right)$