$6m^2+11m-10$
$x^3=-\frac{1}{2}x$
$-5\left(2\left(8\right)-8\left(2\right)\right)$
$\int\frac{x^3+3}{x^2+4x+3}dx$
$2x+3=1-2x+x^2$
$\int\frac{18x^5}{1+3x^6}dx$
$\int\frac{x}{\left(x+3\right)\left(x-1\right)}dx$
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