$\left(x+9\right)^2\left(x+18\right)^2$
$9\left(-5\right)+11$
$\left(-3x^2+3x\right)^3$
$y'+by=d$
$\left(x^2+4xy+5y^2\right)\cdot\left(x-3y\right)$
$123-456$
$\frac{\cos\left(x\right)}{\sin\left(x\right)\cot^2\left(x\right)}=\tan\left(x\right)$
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