$\frac{14x^4}{16x^3}$
$\frac{1}{\left(x-4\right)\left(x-1\right)\left(x-2\right)}$
$\int\frac{\left(x^2-10x+25\right)}{\left(11+10x-x^2\right)^{\frac{3}{2}}}dx$
$4x^4-4x$
$x^3+x-2$
$\left(2+2\right)\cdot\left(-4\right)$
$\frac{1-\sqrt{-7}}{4}$
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