$36x^2+60x+10$
$16x^2-40x=11$
$\left(x-y\right)^2+4\left(x-y\right)z+4z^2$
$a^2-b^2=36$
$\lim\:_{x\to\:\infty\:}\left(\frac{\left(\sqrt{x}+4x^2\right)}{2x-x^2}\right)$
$v^{2}+10uv+2sv^{2}$
$\left(2x-5\right)^2=3y^2$
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