$x^5+4x^3y^2+3y^2=8$
$\lim_{x\to1}\left(\frac{8x-8}{\ln\left(x^4\right)}\right)$
$4a^2-5a+3$
$\sqrt{0.01}$
$\left(\sqrt{1-x}\right)\left(1+x\right)$
$3\cdot\left(4+6\right)$
$\sin x\left(\csc x-\sec x\right)=1-\tan$
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