$\sqrt[3]{-125}+6^2+5\cdot\left|\left(-2\right)^3\cdot4^0\right|^1$
$25x^2-100x+100=0$
$-3t+4=19$
$\pi\left(6.6\right)^2$
$y'=y-2y^2$
$y^4-40y^2+144$
$\lim_{x\to\infty}\left(6x^2-2x-4\right)$
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