$12.4-.75$
$\frac{d^{2}y}{dx^{2}}\text{given}y^{2}=6-\frac{5}{x}$
$m\:^2\:\left(3a+2\right)\:^2$
$\left(v-3z\right)^2$
$\frac{dy}{dx}=\frac{1}{1+x^2}+x^2$
$\left(x^3+6x^2+8x+3\right)-\left(-2x^2-3x^3-6x-4\right)$
$\left(d+5\right)\left(d-5\right)$
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