$\frac{160}{\frac{1}{3}}$
$\left(1+u\right)\left(u+\left(u\right)^'x\right)=1-u$
$3^2+6^2+2$
$\int z^3n^2dz$
$\left(-25\right)\left(5\right)\left(-3\right)$
$\frac{dy}{dx}+x^4y\:=\:4x^4$
$3x^2-34x+70$
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