$\frac{dy}{dx}\left(4x^3y^2-4x^2y=6\right)$
$24\:\frac{dy}{dx}+6y=240$
$\frac{\left(-20\right)}{5}$
$3xy^3-2y+xy^2-xy=0$
$\left(-32\right)^{1.2}$
$b^2.b^0$
$2x-1=-7$
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