$\int\frac{x^2}{\left(\sqrt{3+4x-4x^2}\right)}dx$
$x^2-8x+10=3$
$-\left(-4\right)^6-5\left(4\right)^4+5\left(-4\right)^2-58\:$
$x^3y^3\:-\:y^3$
$\left(\frac{dy}{dx}\right)^2+y^2+3=0$
$\frac{x^2-x-6}{3x^2+x}$
$m\left(m+1\right)-\frac{3}{2}\left(1+m\right)=0$
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