$\left(6x^4+1y^6\right)\left(6x^4-y^6\right)$
$3\left(\infty\right)^3$
$3\sqrt{24}$
$\lim_{x\to0}\left(\frac{1}{x^8}-\frac{1}{x^3}\right)$
$x^5+\frac{-2}{x}-3$
$16a^2b^4+48ab^2y^3+36x^2y^6$
$\frac{d}{dx}\left(\left(e^t\right)\left(2x\right)\right)$
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