$16^9$

$\left(2a+3\right)\left(4a-5\right)$

$\left(0.35\right)-\left(-0.30\right)$

$\frac{dy}{dx}=t\left(x+1\right)^2$

$\lim_{x\to\infty}\left(\frac{\left(\ln\left(x+1\right)\right)^2}{\left(\ln\left(x+2\right)\right)^2}\right)$

$\int3\left(\ln\:\left(x\right)\right)^3.\:x^{-1}dx$

$2x+\frac{5}{x^3}$