$u+16<7$
$\left(1-x^2\right)y'+xy=2x$
$\lim_{x\to\infty}\left(\frac{ln\left(4x+7\right)}{ln\left(7x+5\right)+1}\right)$
$\left(mn^2-m^2\right)^3$
$xy^{1\:}=4y$
$\arctan\left(xy\right)=\arcsin\left(x+y\right)$
$7cos\:\:+8=1$
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