$\lim_{x\to\infty}\left(\frac{arctan\left(x^2\right)}{x^6}\right)$
$\sqrt[2]{144}cm$
$sec\left(2x\right)-cos\left(2x\right)+1$
$\lim_{x\to0}\left(\frac{tan^2\left(x-2\right)}{x^2-4}\right)$
$-11-\left(-9\right)$
$\sqrt[0]{16}$
$81^{\frac{393}{\infty}}$
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