$\int\frac{3x^2-9}{x^3-9x}dx$
$\frac{3y-3}{y^2-1}\cdot\frac{y-1}{y+2}$
$5+\left|2-\left(4+5-3\right)+6\right|-1-\left(3-5\right)$
$6^7$
$\int\left(\frac{x^3+\sqrt[3]{x}}{x^2}\right)dx$
$7x^2-847$
$9x-4<5x+16$
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