$\frac{x+3}{3x+13}=\frac{-1}{x-5}$
$2ax-3by-6ay+bx$
$\frac{d}{dx}\left(3x^3+3y^2=16\right)$
$12x^2-224x+768$
$\frac{x^3-0x^2+0x+1}{x}$
$7\left(9-x\right)\ge5$
$3x^4y-2x^3y-6x+8y=0\:$
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