$-6y+8$
$\frac{2x^2+x+4}{x^4+4x^2}$
$\csc\:\left(18^{\circ\:\:\:}-2x\right)=\frac{1}{\sin\:\left(3x-42^{\circ\:\:\:\:}\right)}$
$\int\left(\frac{x}{\ln\left(x\right)}\right)dx$
$\left(4x+3+5x-2\right)$
$\left(4x^2+x+1\right)$
$\sqrt{12+2+4}$
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