$\int\frac{1}{x^2\left(x-2\right)^2\left(x^2+4\right)}dx$
$\frac{8}{5}x^2-\frac{6}{5}x^2$
$3x+\frac{x}{2}$
$\frac{1}{4}\cdot8+3$
$\frac{x}{x^2+7x+10}-\frac{1}{x^2+x-20}+\frac{2}{x^2-16}$
$\left(3x^{3}+13x^{2}-13x+2\right):\left(3x-2\right)$
$7=x+3$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!