$\lim_{x\to0}\left(\frac{x^2-3^x}{3x+\ln\left(x\right)}\right)$
$y=\sqrt{x}ex^2\left(x^2+5\right)^{10}$
$x^2-13x+42=0$
$y'=\frac{1}{\left(x-6\right)^8}$
$x^5-x^4+x-1$
$3x^3-x^2y+5xy=y-3x$
$\frac{a^{7}}{a^{7}}$
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