$x^2+7x<-12$
$\left(r^9s^6-r^6s^{12}\right)$
$\lim_{x\to\infty}\left(\frac{2x^5-16x^3}{2x^5}\right)$
$12-4\cdot\left(\frac{15}{5}\right)$
$\lim_{x\to0}\left(x+3\right)^n$
$4-\left(-3\right)^2$
$17\left(6.5\right)$
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