$\frac{d}{dx}x^3-5x^2y+2y^3=7$
$\left(a^4-b^5\right)^2$
$-y^2=x-3$
$\cos\left(2x\right)=-0,5$
$x\cdot y\cdot dx=dy$
$\frac{3}{x^3-4}$
$x^2\:\cdot\frac{du}{dx}=-x$
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