$m=\frac{1}{4}\left(\frac{2}{3}d\right)-20$
$x^2y'-x^2y=0$
$\left(\frac{x^3y^{-1}}{3z^{-3}}\right)^3\left(\frac{y^3}{z^5}\right)$
$r^2+12r+36$
$\int\frac{\left(6x+9\right)}{\left(\sqrt{\left(x^2+3x\right)}\right)}dx$
$11-155-3\:18\:-8\:\:0$
$1-2\sin^2\left(3\right)$
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