$\sec^2x\cot^2x\:=\:\csc^2x$
$y'\:-\:y^2\:-\:y\:=\:0$
$980.34+233.544+33.2$
$50:\:\left(-25\right)+\left\{-9+\left[-2+\left(-6\right):\left(+6\right)\right]\right\}+\left(-72\right):\left(-8\right)$
$3^{2x+2}-15\cdot3^x+1=0$
$12\left(2\right)^3$
$\frac{dy}{dx}\:y=\left(x^2+1\right)^3$
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