$6\left(8x+1\right)$
$x+7<5$
$\lim_{x\to\infty}\left(\frac{4}{4x-3}\right)$
$2x^4+x^2-4x-1-4^4-2x$
$z^8-2z^4+1$
$\frac{2csc2x}{cscx}$
$\frac{dy}{dx}\left(x^2+4xy-y^3=11\right)$
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