$x-2=-4-x$
$y=\frac{x^2+x-6}{x^2-4}$
$\frac{dy}{dx}=\frac{y^2}{\left(1-x\right)}$
$\lim_{x\to4}\left(\frac{x^2-5x+4}{x^2+2x-8}\right)$
$\frac{dy}{dx}=\frac{e^x+2}{y^2}$
$\int\:\left(x^3-3\right)^{\frac{3}{2}}\:5x^2dx$
$\int\frac{7x^2+x+12}{3x^3+12x}dx$
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