$x=\frac{6}{x}-1$
$\int tan\left(9x\right)^4dx$
$\frac{4x+5}{x-3}<3$
$\frac{3x^2}{2x^5}$
$-8m>16$
$\left(\frac{5}{7}ab+1.3a\right)^2$
$sec^4+sec^2$
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