$x-y^2=0$
$3-\frac{18-6}{4}$
$z+6\ge-4$
$-6+8i$
$\int_0^{2\pi}\:\:\frac{1}{4}cos^6xdx$
$\left(6\right)\left(-4\right)\left(8\right)$
$\frac{dy}{dx}+2y=1,\:y\left(0\right)=\frac{5}{2}$
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