$\left(6\:+\:3\right)\:.\:2\:-\:8:4\:$
$\int_e^{\infty}x^3lnxdx$
$\frac{2x^6}{6x^2}$
$125x-0.1x^2$
$tres\:3\:eurs$
$\int\frac{x-2}{\left(x^{2}+1\right)\left(x-1\right)}dx$
$\frac{\sin^2t\left(\sec t+\cos\sec t\right)}{\cos t\tan t}=1+\tan t$
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