$\left(6x^5y^3\right)^2$
$x^3y'=e^{x+y^2}$
$4s+11+s^2+3+2s$
$\frac{\left(x^3-8x-5\right)}{x+3}$
$\frac{\left(3x^2\right)^2}{x^5}$
$\lim_{x\to1}\left(\frac{-1-\sqrt{2-x}}{x-1}\right)$
$25x^2-10x+4$
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