$\left(\frac{\left(6p-3q\right)\left(6p-9q\right)}{\left(3p-9q\right)^2}\right)$

$1-2x-x^2=0$

$y^2>49$

$\frac{d}{dx}\frac{1}{2}t^4\:-\:5t^3\:+\:12t^2$

$\left(x^2-2xz+z^2\right)\left(z^2+2zy+y^2\right)$

$\frac{d}{dx}y^2-6y+9=12x-24$

$\lim_{x\to1}\left(\frac{\ln\left(\sin\left(x\right)\right)}{\left(2x-\pi\right)^2}\right)$