$\frac{4x^2y^3}{2xy^3}$
$\frac{d}{dx}xy\:+\:x^2\:+\:y^2\:=\:12$
$8^{1-\left(0.75\right)}$
$\frac{2}{3x}<12$
$2x^2+x-1$
$16cos^2x-4=0$
$\frac{dy}{dx}-y=e^xy^{\frac{3}{2}}$
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