$4\:in\:x-\frac{1}{3}in\:y$
$\frac{dy}{dx}=\frac{10x+qx}{3+x^2}$
$\ln\left(x\right)+\ln\left(x-5\right)=\ln\left(6x\right)$
$6\sin\left(2x\right)+10\cos\left(x\right)=0$
$\frac{6x^3-10x^2}{2a}\:$
$\left(\frac{4}{5}m-\frac{2}{3}n\right)^2$
$\frac{35x^3y^6}{14x^4y^8}$
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